DDT

I think I might have figured out the problem I was having this morning.

Here's the Truth Nugget: Just because an array can behave like a pointer in some ways, doesn't mean it IS a pointer.

So the problem before was that if I have an array s[10], then just using s in an expression is using the address of the first element of the array - kind of like a pointer.

so:

char s[10];
char *ptr;

I can say:

ptr = s, without having to say explicitly ptr = &s[0] or something like that.

HOWEVER it doesn't go the other way.

I can't say s = ptr.

Why? Because.

DDT. Don't Do That.

Big thanks to http://www.eskimo.com/~scs/cclass/krnotes/sx8c.html

That site has saved me several times. I'd pay good money to have all those notes in a book.